Pre-order: F, B, A, D, C, E, G, I, H

In-order:  A, B, C, D, E, F, G, H, I

From first char F in Pre-order, we are sure that the root of the tree is F.

and from In-order, F divide the tree into two parts, the left one is A, B, C, D, E, the right one is G, H, I.

             /   \
A, B, C, D, E     G, H, I

A, B, C, D, E and B, A, D, C, E become a new buildTree problem. so we can build the tree recursively. the result tree is the left children of F.

Similarly, G, H, I and G, I, H become the right children of F.